Refer to S.A.T. data given in exercise 2.16
Suppose you want to predict the male math score on the basis of the female math score (X) by running the following regression:
exercise 2.16
| year | malesv | femalesv | totalv | malem | femalesm | totalm |
|
1967
|
463
|
468
|
466
|
514
|
467
|
492
|
|
1968
|
464
|
466
|
466
|
512
|
470
|
492
|
|
1969
|
459
|
466
|
463
|
513
|
470
|
493
|
|
1970
|
459
|
461
|
460
|
509
|
465
|
488
|
|
1971
|
454
|
457
|
455
|
507
|
466
|
488
|
|
1972
|
454
|
452
|
453
|
505
|
461
|
484
|
|
1973
|
446
|
443
|
445
|
502
|
460
|
481
|
|
1974
|
447
|
442
|
444
|
501
|
459
|
480
|
|
1975
|
437
|
431
|
434
|
495
|
449
|
472
|
|
1976
|
433
|
430
|
431
|
497
|
446
|
472
|
|
1977
|
431
|
427
|
429
|
497
|
445
|
470
|
|
1978
|
433
|
425
|
429
|
494
|
444
|
468
|
|
1979
|
431
|
423
|
427
|
493
|
443
|
467
|
|
1980
|
428
|
420
|
424
|
491
|
443
|
466
|
|
1981
|
430
|
418
|
424
|
492
|
443
|
466
|
|
1982
|
431
|
421
|
426
|
493
|
443
|
467
|
|
1983
|
430
|
420
|
425
|
493
|
445
|
468
|
|
1984
|
433
|
420
|
426
|
495
|
449
|
471
|
|
1985
|
437
|
425
|
431
|
499
|
452
|
475
|
|
1986
|
437
|
426
|
431
|
501
|
451
|
475
|
|
1987
|
435
|
425
|
430
|
500
|
453
|
476
|
|
1988
|
435
|
422
|
428
|
498
|
455
|
476
|
|
1989
|
434
|
421
|
427
|
500
|
454
|
476
|
|
1990
|
429
|
419
|
424
|
499
|
455
|
476
|
(a) Estimate the preceding model (Eviews)
(b) From the estimated residuals,
find out if the normality assumption can be sustained?
( Suggested
Answer)
(c) Now test the hypothesis that
£]2 = 1 , that is, there is a one to one correspondence
between
male and
female math scores. (Suggested
Answer)
(d) Set up the ANOVA table for this
problem. (Suggested Answer)