INTERIM TEST 2nd semester 98-99
Solutions



 
1.
a. modulus of elasticity;
b. yield strength; 
c. tensile strength; 
d. ductility; and 
e. toughness
 
2.
3. Fracture toughness is given by                (1 mark)

where Y» 1 is a dimensionless factor( that depends on sample geometry), yield stress, and a = flaw size.                                     (1 mark)

So  ,       ( 1 mark)

Therefore the test can prevent flaw-induced fracture from occurring.             ( 1 mark)
 

END

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